KCET2014PhysicsGravitation
A body starts from rest and moves with constant acceleration for ( t ) s. It travels a distance ( x₁ ) in first half of time and ( x₂ ) in next half of time, then
Options
- A( x₂=x₁ )
- B( x₂=2 x₁ )
- C( x₂=3 x₁ )
- D( x₂=4 x₁ )
Correct answer
C. ( x₂=3 x₁ )
Step-by-step solution
Initial velocity =0 and acceleration is constant. Distance travelled in first half of time = ₁ Distance travelled in next half of time =x₂ Therefore, acceleration = x₂-x₁ t² (1) Now, x₁= 1 2 at ² because initial velocity is zero. Substitute in Eq. (1), we get array l a= x₂- 1 2 a t² t² a t²=x₂- 1 2 a t² x₂=a t²+ 1 2 a t² x₂=3 1 2 a t² array Thus x₂=3 x₁