A horizontal force of 5 N is applied on a stationary body of mass 5 kg, which is initially at rest on a frictionless table. The change in kinetic energy of the body in 10 s is

Step-by-step solution

Given, mass of the body m = 5 kg Horizontal force F = 5 N Acceleration of the body a = F m = 5 5 = 1 m/s ^2 Initial velocity u = 0 Time t = 10 s Using the equation of motion v = u + at , v = 0 + 1 10 = 10 m/s Initial kinetic energy K_i = 0 Final kinetic energy K_f = 1 2 mv^2 = 1 2 5 (10)^2 = 250 J Change in kinetic energy K = K_f - K_i = 250 - 0 = 250 J Answer: 250 J