A proton, an electron and an -particle enter at right angles to a uniform magnetic field with the same velocity. If R_p, R_e and R_ are the radii of circular paths of these particles, then

Step-by-step solution

The radius of the circular path of a charged particle in a uniform magnetic field is given by R = mv qB . Since the velocity v and magnetic field B are the same for all particles, R m q . For a proton: R_p m_p e For an electron: R_e m_e e For an -particle: R_ m_ q_ = 4m_p 2e = 2m_p e Since m_e Therefore, R_e R_p > R_e . Answer: R_ > R_p > R_e