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KCET2024PhysicsMagnetic Effects of Current

A particle of specific charge q / m= C kg ⁻¹ is projected the origin towards positive X -axis with the velocity 10 ~ms ⁻¹ in a uniform magnetic field B =-2 k T. The velocity v of particle after time t= 1 12 ~s will be (in ms ⁻¹ )

Options

  1. A5( i + j )
  2. B5( i + 3 j )
  3. C5( 3 i - j )
  4. D5( 3 i + j )

Correct answer

D. 5( 3 i + j )

Step-by-step solution

We know that time period, T= 2 m q B = 2 q m B 1 ~s Since, the particle will be at point P after time, t= 1 12 ~s = T 12 ~s It will be deviated by an angle, =2 / 12=30^ Hence, velocity at point P , v =10 ( 30^ i + 30^ j )=10 ( 3 2 i + 1 2 j )=5( 3 i + j )

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