KCET2013PhysicsMagnetic Effects of Current
A charged particle with a velocity 2 10³ ~ms ⁻¹ passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5 ~T . The magnitude of electric field will be
Options
- A1.5 10³ NC ⁻¹
- B2 10³ NC ⁻¹
- C3 10³ NC ⁻¹
- D1.33 10³ NC ⁻¹
Correct answer
C. 3 10³ NC ⁻¹
Step-by-step solution
The charged particle goes undeflected through both the fields, therefore, force experience by charged particle due magnetic field must be equal to the force experienced by the charge particle due to electric field, i.e., F_ m =F_ e or e v B =e E Given, v=2 10³ ~ms ⁻¹ array lrl and & B & =1.5 ~T Hence, & & =90^ & =v B =2 10³ 1.5 90^ & =3 10³ v / m array