KCET2011PhysicsMagnetic Effects of Current
A particle of charge e and mass m moves with a velocity v in a magnetic field B applied perpendicular to the motion of the particle. The radius r of its path in the field is
Options
- Am v B e
- BB e m v
- Ce v B m
- DB v e m
Correct answer
A. m v B e
Step-by-step solution
Radius of path, r- m v q B Here, q=e So, r= m v e B