KCET2008PhysicsMagnetic Effects of Current
The resultant force on the current loop due to a long current carrying conductor will be
Options
- A10⁻⁴ ~N
- B3.6 10⁻⁴ ~N
- C1.8 10⁻⁴ ~N
- D5 10⁻⁴ ~N
Correct answer
D. 5 10⁻⁴ ~N
Step-by-step solution
Force on and are equal but opposite so their net will be zero. Force between two parallel conductors carrying currents I ₁ and I ₂ F = ₀ 2 I ₁ I ₂ l r where r= distance between two parallel aligned F _ PS &= 10⁻⁷ 2 20 20 15 10⁻² 2 10⁻² &=6 10⁻⁴ ~N ~F _ QR &= 10⁻⁷ 2 20 20 15 10⁻² 12 10⁻² &=1 10⁻⁴ ~N ~F _ net &= F _ PS - F _ QR &=6 10⁻⁴-1 10⁻⁴=5 10⁻⁴ ~N aligned