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KCET2021PhysicsMechanical Properties of Fluids

Two capillary tubes P and Q are dipped vertically in water. The height of water level in capillary tube P is 2 3 of the height in capillary tube Q . The ratio of their diameter is

Options

  1. A2: 3
  2. B3: 2
  3. C3: 4
  4. D4: 3

Correct answer

B. 3: 2

Step-by-step solution

As we know, height of capillary rise or fall of a liquid in a capillary tube is given as array ll & h= 2 T r g & h 1 r ...(i) array where, r is the radius of the capillary tube. Given, height of water level in capillary tube P= 2 3 height of water in capillary tube Q . array ll & h_ P = 2 3 h_ Q or & h_ P h_ Q = 2 3 array From Eq. (i), we can write h_ P h_ Q = r_ Q r_ P radius. So, ( diameter )_ P ( diameter )_ Q = 3 2

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