An ideal fluid flows through a pipe of circular cross section with diameters ( 5 ~cm ) and ( 10 ~cm ) as shown. The ratio of velocities of fluid at ( A ) and ( B ) is

Step-by-step solution

An ideal fluid flow through the pipe as shown in the following figure. Now, (Area) ( _ A v_ A =( Area )_ B v_ B ) [ v_ A v_ B = ( area )_ B ( area )_ A = 10² 5² = 100 25 = 4 1 ] Therefore, ratio of velocities of fluid at ( A ) and ( B ) is ( 4: 1 ).