KCET2023PhysicsMotion in One Dimension
A body is moving along a straight line with initial velocity v₀ . Its acceleration a is constant. After t .seconds, its velocity becomes v . The average velocity of the body over the given time interval is
Options
- Av = v^2-v₀^2 a t
- Bv = v^2+v₀^2 2 a t
- Cv = v^2+v₀^2 a t
- Dv = v^2-v₀^2 2 a t
Correct answer
D. v = v^2-v₀^2 2 a t
Step-by-step solution
Given, aligned & v₁=v₀ & v₂=v aligned acceleration =a for time =t ~s Using Newton's equations of motion, aligned v^2-u^2 & =2 a s s & = v^2-u^2 2 a ( total distance covered ) s & = v^2-v₀^2 2 a aligned Average yelocity = Total distance Total time = v^2-v₀^2 2 a t [Using Eq. (i)] v_ avg = v^2-v₀^2 2 a t