The displacement x (in m ) of a particle of mass m (in kg ) moving in one dimension under the action of a force, is related to time t (in sec) by t= x +3 . The displacement of the particle when its velocity is zero, will be

Step-by-step solution

Displacement of the particle related with time is given as t= x +3 x =t-3 Squaring on both sides, we get array ll & x=(t-3)^2 & x=t^2-6 t+9 array Velocity of the particle, v= d x d t = d d t (t^2-6 t+9 )=2 t-6 when v=0 i.e 2 t-6=0 t=36 i.e velocity of particle is zero at t=3 ~s . Displacement of particle at t=3 ~s , gathered x=3^2-6 3+9 =0 gathered [from Eq. (i)i