Two capacitors of ( 10 pF ) and ( 20 pF ) are connected to ( 200 ~V ) and ( 100 ~V ) sources respectively. If they are connected by the wire, what is the common potential of the capacitors ?

Step-by-step solution

Common potential, ( V= C V₁+C₂ V₂ C₁+C₂ ) ( = 10 10⁻¹² 200+20 10⁻¹¹ 100 10 10⁻¹²+20 10⁻¹² ) ( V= 10⁻¹² 200(1+1) 10⁻¹² 10(1+2) = 200 2 3 =133.33 ~V ) Thus, common potential of the capacitors is ( 133.33 ~V ).