KCET2021PhysicsMotion in Two Dimensions
A particle starts from the origin at t=0 with a velocity of 10 j ms ⁻¹ and move in the x-y plane with a constant acceleration of (8 i +2 j ) ms ⁻² . At an instant when the x -coordinate of the particle is 16 ~m , y -coordinate of the particle is
Options
- A16 ~m
- B28 ~m
- C36 ~m
- D24 ~m
Correct answer
D. 24 ~m
Step-by-step solution
Given, u =10 j ms ⁻¹, a =8 i +2 j ms ⁻²x=16 ~m Using equation of motion, gathered s=u t+ 1 2 a t² x i +y j =10 j t+ 1 2 (8 i +2 j ) t² gathered 16 i +y j =10 t j +4 t² i +t² j Comparing both sides, we get 4 t²=16 t=2 ~s and y=10 t+t²=10 2+(2)²=24 ~m