KCET2011PhysicsMotion in Two Dimensions
The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y=8 t-5 t² ~m and x=6 t ~m , where t is in seconds. The velocity with which the projectile is projected is
Options
- A6 ~ms
- B8 ~ms ¹
- C10 ~ms ⁻¹
- D14 ~ms ⁻¹
Correct answer
C. 10 ~ms ⁻¹
Step-by-step solution
Given, y=8 t-5 t² (i) We know, x=6 t Compare with Eq. (ii), we get u₁ = x t =6 and y=(u ) t- 1 2 g t² Compare with Eq (i), we get aligned u₂ &=8 u &= u₁²+u₂² u &= 36+64 u &=10 ~ms ⁻¹ aligned