KCET2024PhysicsSemiconductors
A p-n junction diode is connected to a battery of emf 5.7 V in series with a resistant 5 k such that it is forward biased. If the barrier potential of the diode is 0.7 V , neglecting the diode resistance, the current in the circuit is
Options
- A1.14 mA
- B1 mA
- C1 A
- D1.14 A
Correct answer
B. 1 mA
Step-by-step solution
Given, barrier potential, V_B=0.7 ~V Series resistance, R_S=5 k =5 10^3 I= V-V_B R_S = 5.7-0.7 5 10^3 =1 10⁻³ ~A =1 ~mA