Three photodiodes D₁, D₂ and D₃ are made of semiconductors having band gaps of 2.5 eV , 2 eV and 3 eV , respectively. Which one will be able to detect light of wavelength 600 ~nm ?

Step-by-step solution

Given, E₁=2.5 eV , E₂=2 eV , E₃=3 eV and =600 ~nm As we know, E= 1242 = 1242 600 =2.07 eV Since, E₁ and E₃ is greater than E . So, only D₂ will able to detect the given light of wavelength 600 nm .