In a transistor, the collector current varies by ( 0.49 ~mA ) and emitter current varies by ( 0.50 ~mA ). Current gain ( ) measured is

Step-by-step solution

Given, collector current variation, ( I_ c =0.49 ~mA ) emittercurrent variation, ( I_ E =0.50 ~mA ) Now, current gain, [ array l = I_ C I_ B = I_ C I_ E - I_ C = 0.49 ~mA (0.50-0.49) mA = 0.49 ~mA 0.01 ~mA =49 array ] Therefore, current gain ( ) is ( 49 ).