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KCET2015PhysicsSemiconductors

A particle is projected with a velocity ( v ) so that its horizontal range twice the greatest height attained. The horizontal range is

Options

  1. A( v² g )
  2. B( 2 v² 3 g )
  3. C( 4 v² 5 g )
  4. D( v² 2 g )

Correct answer

C. ( 4 v² 5 g )

Step-by-step solution

Velocity of particle =v Horizontal range =2 Greatest height attained Now, Range = v² 2 g Height = v² ² 2 g v² 2 g = 2 v² ² 2 g 2 = ² Using, 2 =2 , we get 2 = ² 2 = =2 tan =2 = 2 5 and = 1 5 Therefore, Range = v² 2 g = 2 v² g = 2 v² g 2 5 1 5 = 4 5 v² g Horizontal range = 4 5 v² g

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