100 ~g of ice at 0^ C is mixed with 100 ~g of water at 100^ C . The final temperature of the mixture is [Take, L_f=3.36 10^5 ~J ~kg ⁻¹ and .S_w=4.2 10^3 ~J ~kg ⁻¹ ~K ⁻¹ ]

Step-by-step solution

Let the final temperature of mixture be T . Heat absorbed by ice = heat lost by water mL+m c(T-0)=m c(100-T) Substituting values, aligned & (100 80)+(100 1) T=100 1(100-T) & 8000+100 T=10000-100 T & 200 T=2000 & T=10^ C & aligned