0.1 ~m ³ of water at 80^ C is mixed with 0.3 ~m ³ of water at 60^ C . The final temperature of the mixture is

Step-by-step solution

Let the final temperature of the mixture be t Heat lost by water at 80^ C aligned &= ms t &=0.1 10³ s _ water (80^ - t ) & ( m = V d =0.1 10³ ~kg ) aligned Heat gained by water at 60^ C =0.3 10³ s _ water ( t -60^ ) According to principle of calorimetry Heat lost = Heat gained 0.1 10³ s _ water (80^ - t )=0.3 10³ s_ water (t-60^ ) or (80^ - t )=3 ( t -60^ ) or 4 t =260^ or t =65^ C