A stone is thrown vertically at a speed of ( 30 ~ms ⁻¹ ) making an angle of ( 45^ ) with the horizontal. What is the maximum height reached by the stone? Take ( g=10 ~ms ⁻² ).

Step-by-step solution

Given, speed ( =30 ~ms ⁻¹ ), angle of projection ( =45^ ; g=10 ~ms ⁻² ) Maximum height reached by the stone is [ array l H= v² ² 2 g = (30)²( 45)² 2 10 = 900 1 2 2 10 = 900 1 2 2 10 H= 90 4 =22.5 array ] Therefore, maximum height reached by stone is ( 22.5 ~m ).