KCET2018PhysicsUnits and Dimensions
The dimensions of the ratio of magnetic flux ( ( ) ) and permeability ( ( ) ) are
Options
- A( [M⁰ L¹ T⁰ A¹ ] )
- B( [M⁰ L⁻³ T⁰ A¹ ] )
- C( [M⁰ L¹ T¹ A^ (-1) ] )
- D( [M⁰ L² T⁰ A¹ ] )
Correct answer
A. ( [M⁰ L¹ T⁰ A¹ ] )
Step-by-step solution
Magnetic flux, =B A (1) where B is magnetic field; A is area. Also, B= H (2) where is permeability; H is magnetic field intensity Substituting Eq. (2) in Eq. (1), we get =( H) A or =H A Now, Area A has dimensions L² And magnetic field intensity H= Number of turns Current Metre H has dimensions L⁻¹ A . Therefore, =L⁻¹ A L²=L A Hence, the dimensions of ratio of magnetic flux and permeability are [M⁰ L¹ T⁰ A¹ ]