KCET2023PhysicsWave Optics
In the Young's double slit experiment, the intensity of light passing through each of the two double slits is 2 10⁻² Wm ⁻² . The screen-slit distance is very large in comparison with slit-slit distance. The fringe width is . The distance between the central maximum and a point P on the screen is x= 3 . Then, the total light intensity at the point is
Options
- A8 10⁻² Wm ⁻²
- B4 10⁻² Wm ⁻²
- C2 10⁻² Wm ⁻²
- D16 10⁻² Wm ⁻²
Correct answer
C. 2 10⁻² Wm ⁻²
Step-by-step solution
Given, x= 3 I₀=2 10⁻² Wm ⁻² for YDSE where D d, x=d Also x D = 3 D = D d 3 D = 3 d aligned & = 2 x= 2 d = 2 d 3 d = 2 3 = & I=4 I₀ ^2 ( 2 )=4 I₀ ^2 ( 2 3 1 2 ) & =4 I₀ ^2 ( 3 )=4 I₀ 1 4 aligned I=I₀=2 10⁻² ~W ~m ⁻²