In a system of two crossed polarisers, it is found that the intensity of light from the second polariser is half from that of first polariser. The angle between their pass axes is

Step-by-step solution

By Malus Law, we have [ I=I₀ ] Given, intensity of light from second polariser is half of that from the first polariser, so [ array l I₀ 2 =I₀ ² ² = 1 2 = 1 2 = ⁻¹ ( 1 2 ) =45^ array ] Therefore, angle between the pass axes of polarisers is ( 45^ ).