KCET2016PhysicsWave Optics
Light of wavelength ( 600 ~nm ) is incident normally on a slit of width ( 0.2 ~mm ). The angular width of central maxima in the diffraction pattern is (measured from minimum to minimum)
Options
- A( 6 10⁻³ rad )
- B( 4 10⁻³ rad )
- C( 2.4 10⁻³ rad )
- D( 4.5 10⁻³ rad )
Correct answer
A. ( 6 10⁻³ rad )
Step-by-step solution
Given, wavelength, =600 ~nm =600 10⁻⁹ ~m width of slit, a=0.2 ~mm =0.2 10⁻³ ~m Angular width of central maxima = 2 a = 2 600 10⁻⁹ 0.2 10⁻³ =600 10⁻⁵=6 10⁻³ Therefore, angular width of central maxima =6 10⁻³ rad