KCET2010PhysicsWave Optics
The wavelength of the light used in Young's double slit experiment is . The intensity at a point on the screen is I, where the path difference is 6 . If I ₀ denotes the maximum intensity, then the ratio of I and I ₀ is
Options
- A0.866
- B0.5
- C0.707
- D0.75
Correct answer
D. 0.75
Step-by-step solution
Phase difference, = 2 path difference = 2 6 = 3 =60^ Intensity, I = I ₀ ² ( 2 ) I I ₀ = ² (30^ )= ( 3 2 )²=0.75