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KCET2014PhysicsWaves and Sound

What is a period of revolution of earth satellite ? Ignore the height of satellite above the surface of earth. Given : (1) The value of gravitational acceleration ( g=10 ~ms ⁻² ). (2) Radius of earth ( R_ E =6400 ~km ). Take ( =3.14 ).

Options

  1. A( 85 ) minutes
  2. B( 156 ) minutes
  3. C( 83.73 ) minutes
  4. D( 90 ) minutes

Correct answer

C. ( 83.73 ) minutes

Step-by-step solution

Given, gravitational acceleration, g=10 ~ms ⁻¹ radius of Earth, R_ E =6400 ~km =6400 10³ ~m We know, period of revolution of Earth satellite is given as T=2 R_ E g =2 3.14 6400 10³ 10 =2 3.14 80 10 Therefore T=5024 ~s = 5024 60 ~min =83.733 ~min Thus, period of revolution of Earth satellite is 83.73 minutes.

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