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KCET2013PhysicsWaves and Sound

The equation of a transverse wave is given by y=0.05 (2 t-0.02 x) , where x, y are in metre and t is in second. The minimum distance of separation between two particles which are in phase and the wave velocity are respectively

Options

  1. A50 ~m , 50 ~ms ⁻¹
  2. B100 ~m , 100 ~ms ⁻¹
  3. C50 ~m , 100 ~ms ⁻¹
  4. D100 ~m , 50 ~ms ⁻¹

Correct answer

B. 100 ~m , 100 ~ms ⁻¹

Step-by-step solution

Given, y=0.05 (2 t-0.02 x) or y=0.05 (2 t-0.02 x) On comparing this equation with standard equation y=a ( t-k x) where = 2 T and K= 2 , we have 2 =0.02 =100 ~m Also, = 2 T =2 or 1 T =1 v=1 So, v=r =1 100=100 ~m / s

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