A cylindrical tube open at both the ends has a fundamental frequency of 390 ~Hz in air. If 1 4 th of the tube is immersed vertically in water the fundamental frequency of air column is

Step-by-step solution

Fundamental frequency of cylindrical open tube n = v 2 ~L =390 ~Hz When it is immersed in water it becomes a closed tube of length 3 4 th of the initial length. Therefore, its fundamental frequency is aligned n ^ &= V 4 ( 3 4 ~L ) = v 3 ~L = 2 3 ( V 2 ~L ) &= 2 3 390 ~Hz =260 ~Hz aligned