A particle of mass 500 g is at rest. It is free to move along a straight line. The power delivered to the particle varies with time according to the following graph The momentum of the particle at t=5 ~s is

Step-by-step solution

Area under P -t graph is equal to work done (or change in kinetic energy) k= P^2 2 m = area of region O A B C P^2 2 m = (2+8) 5 2 P^2 2 0.5 =25 [ m=500 ~g =0.5 ~kg ] P^2=25 P=5 ~kg ~ms ⁻¹