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KVPY2019ChemistryChemical Bonding and Molecular Structure

The hybridisations of N , C and O shown in the following compound respectively, are

Options

  1. As p 2 , s p , s p 2
  2. Bs p 2 , s p 2 , s p 2
  3. Cs p 2 , s p , s p
  4. Ds p , s p , s p 2

Correct answer

A. s p 2 , s p , s p 2

Step-by-step solution

Hybridisation is determined from the steric number (number of atoms bonded to the central atom + the number of lone pairs). Number of hybrid orbitals must be equal to the steric number. From the Lewis structure. (i) Steric number of N-atom = 3 (2 bonded atoms +1 lone pair), ∴ Hybridisation = s p 2 (3 hybrid orbitals). (ii) Steric number of C-atom = 2 (2 bonded atoms), ∴ : Hybridisation = s p ( 2 hybrid orbitals). (iii) Steric number of 0 -atom = 3 (1 bonded atom +2 lone pair) ∴ Hybridisation = sp 2 ( 3 hybrid orbit

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