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KVPY2019ChemistryChemical Bonding and Molecular Structure

The diamagnetic species among the following is

Options

  1. AO 2 +
  2. BO 2 -
  3. CO 2
  4. DO 2 2 -

Correct answer

D. O 2 2 -

Step-by-step solution

To be diamagnetic, no unpaired electron must be present. Hint Write molecular orbital electronic configuration of each species. For all options given, σ 1 s 2 σ 1 s ⋆ 2 σ 2 s 2 σ 2 s * 2 σ 2 p z 2 π 2 p x 2 = π 2 p y 2 is common. After that, O 2 + : π 2 p x * 1 , O 2 - : π 2 p x * 2 = π 2 p y * 1 , and O 2 : π 2 p x * 1 = π 2 p y * 1 , all contain unpaired electron. They are paramagnetic, but O 2 2 - : π 2 p x * 2 = π 2 p y ⋆ 2 has no

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