Among the following, the species with identical bond order are

Step-by-step solution

The bond order can be calculated as B . O = 1 2 N b - N a Where, N b = Electrons in bonding orbitals N a = Electrons in anti bonding orbitals. (a) C O and O 2 2 - The electronic configuration of C O (14) is σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 σ * 2 p z 2 π 2 p x 2 π 2 p 2 y ∴    B . O = 1 2 ( 10 - 4 ) = 6 2 = 3 (b) O 2 - and C O The electronic configuration of 0 2 - ( 17 ) is σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 σ 2 p z 2 π 2 p x 2 &#96