KVPY2018ChemistryIonic Equilibrium
The solubility of B a S O 4 in pure water (in g L - 1 ) is closest to Given; K sp for B a S O 4 is 1 . 0 × 10 - 10 at 25 ° C . Molecular weight of B a S O 4 is 233   g   m o l - 1 ]
Options
- A10 × 10 - 5
- B10 × 10 - 3
- C2 . 3 × 10 - 5
- D2 . 3 × 10 - 3
Correct answer
D. 2 . 3 × 10 - 3
Step-by-step solution
Given, K sp = 1 × 10 - 10 BaSO 4 ⇌ Ba 2 + + SO 4 2 -                                             S                           S Let the solubity of B a 2 + and S O 4 2 - be S ∴    K s p = S 2 1 × 10 - 10 = S 2 S = 10 - 5   m o l / L Thus, solubility of BaSO 4 in pure water (in g/L) Solubility (in mol/L)