KVPY2019ChemistryIonic Equilibrium
Solubility products of CuI and Ag 2 CrO 4 have almost the same value ~ 4 × 10 - 12 . The ratio of solubilities of the two salts CuI : Ag 2 CrO 4 is closest to
Options
- A0 . 01
- B0 . 02
- C0 . 03
- D0 . 10
Correct answer
B. 0 . 02
Step-by-step solution
CuI s ⇌ Cu + aq + I - aq K sp = Cu + I - If its solubility = x , at equilibrium . , Cu + = x and I - = x , K sp = x 2 . Since, K sp = 4 × 10 - 12 , x = 2 × 10 - 6   M Ag 2 CrO 4 s ⇌ 2 Ag + aq + CrO 2 - aq K sp = Ag + 2 CrO 4 2 - If its solubility = y , at eqbm . , Ag + = 2 y and CrO 4 2 - = y ∴   K sp = 2 y 2 y = 4 y 3 Since, K sp = 4 × 10 - 12 , 4 y 3 = 4 × 10 - 12 , y = 10 - 4   M ∴   x : y = 2 × 10 - 6 ; 10 - 4 = 2 × 10 - 2 = 0 . 02