KVPY2018ChemistryIonic Equilibrium
A buffer solution can be prepared by mixing equal volumes of
Options
- A0 . 2   M   NH 4 OH and 0 . 1   M   HCl
- B0 . 2   M   NH 4 OH and 0 . 2   M   HCl
- C0 . 2   M   NaOH and 0 . 1   M   CH 3 COOH
- D0 . 1   M   NH 4 OH and 0 . 2   M   HCl
Correct answer
A. 0 . 2   M   NH 4 OH and 0 . 1   M   HCl
Step-by-step solution
The solutions which resist change in pH on dilution or with the addition of small amounts of acid or alkali are called buffer solution. It is a mixture of weak base with its salt or weak acid with its salt. Thus, buffer solution can be prepared by mixing equal volumes of 0 . 2   M   NH 4 OH (weak base) and 0 . 1   M   HCl (strong acid). It results in the formation of NH 4 OH (weak base) + NH 4 Cl (salt of weak base NH 4 OH ), which is a basic buffer mixture.