KVPY2020Chemistryp Block Elements (Group 13 & 14)
Sodium borohydride upon treatment with iodine produces a Lewis acid ( X ) , which on heating with ammonia produces a cyclic compound Y and a colorless gas Z .   X ,   Y and Z are
Options
- AX = BH 3 ; Y = BH 3 . NH 3 ; Z = N 2
- BX = B 2 H 6 ; Y = B 3   N 3 H 6 ; Z = H 2
- CX = B 2 H 6 ; Y = B 6 H 6 ; Z = H 2
- DX = B 2 H 6 ; Y = B 3   N 3 H 6 ; Z = N 2
Correct answer
B. X = B 2 H 6 ; Y = B 3   N 3 H 6 ; Z = H 2
Step-by-step solution
2 Na BH 4 + I 2 ⟶ B 2 H 6 X + 2 NaI + H 2 3   B 2 H 6 + 6 NH 3 ⟶ Δ 2   B 3   N 3 H 6 Y + 12 H 2 Z X = B 2 H 6 Y = B 3   N 3 H 6 Z = 12 H 2