When 262 ~g of xenon (atomic mass =131 ) reacted completely with 152 ~g of fluorine (atomic mass =19 ), a mixture of XeF ₂ and XeF ₆ was produced. The molar ratio XeF ₂: XeF ₆ is :

Step-by-step solution

Xe + F ₂ XeF ₂+ XeF ₆ 262 131 152 38 a mole b mole =2 mole 4 mole Let a mole XeF ₂ form and b mole XeF ₆ form Apply POAC array ll a 1+ b 1=2 2 a +6 ~b =8 array After solving eq. (1) &(2) a =1 mole & ~b =1 ~mole