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KVPY2019ChemistrySolutions

The values of the Henry's law constant of Ar ,   CO 2 ,   CH 4 and O 2 in water at 25 ° C are 40 . 30 ,   1 . 67 ,   0 . 41 and 34 . 86   kbar , respectively. The order of their solubility in water at the same temperature and pressure is

Options

  1. AAr > O 2 > CO 2 > CH 4
  2. BCH 4 > CO 2 > Ar > O 2
  3. CCH 4 > CO 2 > O 2 > Ar
  4. DAr > CH 4 > O 2 > CO 2

Correct answer

C. CH 4 > CO 2 > O 2 > Ar

Step-by-step solution

By Henry's law, p gas   ∝ X gas   (in liquid solution) and p gas   = K H × χ gas   K H = Henry's law constant. ∴ At a given partial pressure of gas, K H ∝ 1 χ gas ∴ The greater the value of K H , the less its solubility. Here, K H of Ar > O 2 > CO 2 > CH 4 . ∴ Solubility of CH 4 > CO 2 > O 2 > Ar .

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