KVPY2019ChemistrySolutions
The values of the Henry's law constant of Ar ,   CO 2 ,   CH 4 and O 2 in water at 25 ° C are 40 . 30 ,   1 . 67 ,   0 . 41 and 34 . 86   kbar , respectively. The order of their solubility in water at the same temperature and pressure is
Options
- AAr > O 2 > CO 2 > CH 4
- BCH 4 > CO 2 > Ar > O 2
- CCH 4 > CO 2 > O 2 > Ar
- DAr > CH 4 > O 2 > CO 2
Correct answer
C. CH 4 > CO 2 > O 2 > Ar
Step-by-step solution
By Henry's law, p gas   ∝ X gas   (in liquid solution) and p gas   = K H × χ gas   K H = Henry's law constant. ∴ At a given partial pressure of gas, K H ∝ 1 χ gas ∴ The greater the value of K H , the less its solubility. Here, K H of Ar > O 2 > CO 2 > CH 4 . ∴ Solubility of CH 4 > CO 2 > O 2 > Ar .