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KVPY2014ChemistryStates of Matter

The volume of oxygen at STP required to burn 2.4 ~g of carbon completely is

Options

  1. A1.12 ~L
  2. B8.96 ~L
  3. C2.24 ~L
  4. D4.48 ~L

Correct answer

D. 4.48 ~L

Step-by-step solution

C(s)+O₂(g) C O₂(g) moles =1 mole 1 mole 1 mole weight =12 g m 32 g m 44 g m12 g m of C require 1 mole of O₂ volume of 2.4 / 12 mole O ₂ at STP = 22.4 2.4 12 litre 4.48 litre

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