AP EAMCET202422 May 2024Morning ShiftChemistrySolutionsActual
At T ( K ) two liquids A and B form an ideal solution. The vapour pressures of pure liquids A and B at that temperature are 400 and 600 mm Hg respectively. If the mole fraction of liquid B is 0.3 in the mixture, the mole fractions of A and B in vapour phase respectively are
Options
- A0.391,0.609
- B0.509,0.491
- C0.609,0.391
- D0.491,0.509
Correct answer
C. 0.609,0.391
Step-by-step solution
aligned & P _ A ^0=400 & P _ B ^0=600 & x _ A =0.7 & x _ B =0.3 [ x _ A + x _ B =1 ] & P _ A = P _ A ^0 x _ A & P _ A =0.7 400=280 & P _ B = P _ B ^0 x _ B & =0.3 600=180 & P _ T = P _ A + P _ B =460 & . In vapour phase ^2+ x _ B =1 ] & P _ A = P _ T X ₁ ~A & P _ B = P _ T X ₁ ~B & X ₁ ~A = 280 460 =0.61 & X ₁ ~B = 180 460 =0.39 aligned