AP EAMCET202421 May 2024Evening ShiftChemistrySolutionsActual
Given below are two statements. Statement I: Liquids A and B form a non-ideal solution with negative deviation. The interactions between A and B are weaker than A - A and B - B interactions Statement II: In reverse osmosis, the applied pressure must be higher than the osmotic pressure of solution The correct answer is
Options
- ABoth Statement-I and Statement-II are correct
- BBoth Statement-I and Statement-II are not correct
- CStatement-I is correct but Statement-II is not correct
- DStatement-I is not correct but Statement-II is correct
Correct answer
D. Statement-I is not correct but Statement-II is correct
Step-by-step solution
In case of negative deviations from raoult's law, the intermolecular attractive forces between A - A and B - B are weaker than those between A-B and leads to decrease in vapour pressure resulting in negative deviations. In reverse osmosis the applied pressure must be higher than the osmotic pressure of solution. Hence Statement I is incorrect but II is correct.