At 293 K , methane gas was passed into 1 L of water. The partial pressure of methane is 1 bar . The number of moles of methane dissolved in 1 L water is ( K _ H . of methane =0.4 kbar )

Step-by-step solution

According to Henry's Law, aligned & p = K _ H x & p = partial pressure & K _ H = Henery constant aligned x = mole fraction given p =1 bar aligned & K _ H =0.4 10^3 bar [1 ~K bar =10^3 bar ] & p = K _ H x aligned aligned & 1 bar =0.4 10^3 bar x & x= 1 0.4 10^3 aligned aligned & n _ methane n _ methane + nH ₂ O = 1 0.4 10^3 & n _ methane nH ₂ O aligned aligned & n _ methane nH ₂ O = 1 0.4 10^3 & n _ methane nH ₂ O = 1 0.4 10^3 [ nH ₂ O = 1000 18 =55.55 ~mol ] aligned aligned & = 55.55 0.4 10^3 & =138 10⁻¹ aligned n _