What is the depression of freezing point, when mole fraction of non-electrolyte solute in aqueous solution is 0.01 ? ( ~K _ f . of . H ₂ O =1.86 ~K ~kg ~mol ⁻¹ )

Step-by-step solution

T _ f = m K _ f = n ₂ ~m ₁ K _ f We have, x ₂= n ₂ n ₁+ n ₂ n ₂ n ₁ =0.01 Taking 1 ~L of water, mass of water =1 ~kg =1000 ~g aligned & n ( H ₂ O )= n ₁= 1000 ~g 18 ~g ~mol ⁻¹ =55.55 ~mol & n ₂=55.55 0.01=0.556 ~mol & T _ f = n ₂ ~m ₁ K _ f = 0.556 ~mol 1 ~kg 1.86 & =1.034 ~K 1.043 ~K aligned