KVPY2015MathematicsFunctions
For a real number x , let [x] denote the largest integer less than or equal to x , and let x =x-[x] . The number of solutions x to be equation [x] x =5 with 0 x 2015 is
Options
- A0
- B3
- C2008
- D2009
Correct answer
D. 2009
Step-by-step solution
array l x =x-[x] [x] x =5 f 0 I f=5 0 < f < 1 array Possible solutions (6+ 5 6 ), (7+ 5 7 ), ., (2014+ 5 2014 )=2009