KVPY2020MathematicsLimits
Define a sequence s n of real numbers by S n = ∑ k = 0 n 1 n 2 + k '    for  n ≥ 1 Then lim n → ∞ s n
Options
- Adoes not exist
- Bexists and lies in the interval ( 0 , 1 )
- Cexists and lies in the interval [ 1 , 2 )
- Dexists and lies in the interval [ 2 , ∞ )
Correct answer
C. exists and lies in the interval [ 1 , 2 )
Step-by-step solution
Since, ∑ k = 0 n 1 n 2 + n ≤ ∑ k = 0 n 1 n 2 + k ≤ ∑ k = 0 n 1 n 2 + 0 ⇒ lim n → ∞ n n 2 + n ≤ lim n → ∞ S n ≤ lim n → ∞ n n 2 ⇒ 1 ≤ lim n → ∞ S n ≤ 1 ⇒ lim n → ∞ S n ≤ 1