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KVPY2011MathematicsParabola

In the x y -plane, three distinct lines l₁, l₂, l₃ concur at a point ( , 0) . Further the lines l₁, l₂, l₃ are normals to the parabola y²=6 x at the points A= (x₁, y₁ ), B= (x₂, y₂ ), C= (x₃, y₃ ) respectively. Then we have -

Options

  1. A< -5
  2. B>3
  3. C-5 < < -3
  4. D0 < < 3

Correct answer

B. >3

Step-by-step solution

Any normal y = mx -2 am - am ³ Here a =3 / 2 through ( , 0) array l 0= m -2 am - am ³ ~m =0, =2 a + am ² ~m ²= a -2>0 >2 a >3 array

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