6 ~g of a non-volatile solute ( x ) is dissolved in 100 ~g of water. The relative lowering of vapour pressure of resultant solution is 0.006 . What is the molar mass (in g mol ⁻¹ ) of x ?

Step-by-step solution

aligned & P P ^0 =0.006, ~m ₁=100 ~g , ~m ₂=6 ~g , M ₁=18.0 ~g ~mol ⁻¹ & P P ^0 = x ₂= n ₂ n ₁+ n ₂ n ₂ n ₁ ( n ₁ n ₂ ) & n ₂= P P ^0 n ₁=0.006 100.0 18.0 =0.0334 & M ₂= m ₂ n ₂ = 6.0 0.0334 180 ~g ~mol ⁻¹ aligned