KVPY2016MathematicsProbability
If a 3-digit number is randomly chosen, what is the probability that either the number itself or some permutation of the number (which is a 3 -digit number) is divisible by 4 and 5 ?
Options
- A1 45
- B29 180
- C11 60
- D1 4
Correct answer
B. 29 180
Step-by-step solution
We need 3 -digit number which is divisible by 4 & 5 both. i.e. their last two digits are 00,20,40,60 & 80 Now, ending with 00 are '9'. 100,200, , 900 If digit repeat other than ' 0 ' then they are 220,440,660,880 but 220 numbers can be permuted according to the condition as 220,202 So, there are ' 8 ' other favorable cases. If the number have no digit repeated like 320 . 320 can be permuted in 4 ways. 302,230,320,203 So, such numbers are 8 4 4=128 Total favorable =9+8+128=145 So, required prob. = 145 900 = 29 180