At T ( K ) , the partial pressure of dissolved oxygen in 1 ~L water is 1 bar. The concentration of oxygen is ppm is ( K _ H . of O ₂ at T ( K ) is .50 kbar )

Step-by-step solution

According to Henry's Law, P _ O ₂ = K _ H _ O ₂ ; P _ O ₂ =1 bar, ( K _ H )_ O ₂ =50 ~K bar at T ( K ) 50 10^2 _ O ₂ =1 or _ O ₂ = 10⁻³ 50 or n _ O ₂ n _ O ₂ + n _ H ₂ O = 10⁻³ 50 Approximating n _ O ₂ n _ H ₂ O , n _ O ₂ n _ H ₂ O = 10⁻³ 50 [1 ~L H ₂ O =55.5 ~mol H ₂ O ] n _ O ₂ = 55.5 10⁻³ 50 =35.5 10⁻³ ~mol The concentration of Oxygen in ppm aligned & = 35.5 10⁻³ 10^6 10^3 & =35.5 aligned